| Then, because B always calls the same side as she flips, she will be wrong. There are only 2 outcomes. Either they flip the same or they flip differrently. As long as they guess differently between these 2 outcomes, 1 will always be wrong. |
Zymf said: There are only 2 outcomes. Either they flip the same or they flip differrently. As long as they guess differently between these 2 outcomes, 1 will always be wrong. Okay, now I understand. |
You will be what you will to be. |
| It's been 48 hours so here's a new one. This one's easy so no complaints -_- What's the next umber in the following sequence: 5961, 1596, 6159...? |
| 9615 |
You will be what you will to be. |
 |
| gone bai bai |
| Interesting math bit with the riddle. 5961 - 1596 = 4365 6159 - 1596 = 4563 9615 - 6159 = 3456 |
 |
Switch-kun said: 9615 You're right ^^ |
| Okay, so here's the next riddle - Four jolly men sat down to play, they played all night until the break of day. They played for cash and not for fun, with a separate score for every one. When it came time to square accounts, they all made quite fair amounts. Not one lost and all gained. Now that you've heard, can you explain? |
You will be what you will to be. |
| Hmm, I've been thinking about this for a few minutes now. What were they playing? What does the separate score part mean? Is the no one lost part an overall result? If it's cards they're, then they weren't playing with each other. If it's another kind of playing, they're in an orchestra? because then they'd all get paid and each would have a musical score (sheet music) in front of them (separate score). I can't think of other explanations, unless they all played cards/other types of gambling games and won more than they lost. So by the end of the night, there were no losses, only gains. ┐(‘～`；)┌ |
grave_robber said: If it's another kind of playing, they're in an orchestra? because then they'd all get paid and each would have a musical score (sheet music) in front of them (separate score). Well, I just picked up a riddle in a hurry, so sorry for such a riddle. This is the correct answer. |
You will be what you will to be. |
| It was a good riddle, I like ones that require a bit of thinking ^^ New Puzzle "A sultan tells his two sons to race their camels to a distant city to see who will inherit his fortune. The one whose camel is slower wins. After wandering aimlessly for days, the brothers ask a wise man for guidance. Upon receiving the advice, they jump on the camels and race to the city as fast as they can. What did the wise man say to them?" |
| He asked them to switch their camels. |
El-Psy_Congroo said: He asked them to switch their camels. That is correct. |
| [b]So there's this king. Someone breaks into his wine cellar where he stores 1000 bottles of wine. This person proceeds to poison one of the 1000 bottles, but gets away too quickly for the king's guard to see which one he poisoned or to catch him. The king needs the remaining 999 safe bottles for his party in 4 weeks. The king has 10 servants who he considers disposable. The poison takes about 3 weeks to take effect, and any amount of it will kill whoever drinks it. How can he figure out which bottle was poisoned in time for the party? |
| But if the servants start drinking of the 999 safe bottles to test if it's poisoned, then there will not be 999 full bottles for the party? Disregarding this fact I'd do the following: Day 1: Split the 1000 bottles in 10 groups of 100 and have the servants take a sip from every single bottle in each group. Day 2: Split each group in half and make 10 new groups and have the servants take a sip from every single bottle in the new groups. Day 3: Split the groups in half again and make 10 new groups so that only 25 of the bottles from Day 1 remains (you get the idea) and have the servants take a sip from every single bottle in the new groups. Day 4-6: Keep splitting the groups in half, forming new unique groups. Day 7: Split the groups in half one last time and have the servants take a sip from every single bottle in the new groups. Since there initially was 100 bottles in each group, there will only be 100*0.5^7 ≈ 1 bottle from from Day 1 remaining in each group. Now I'd wait 2 weeks till my servants would begin dying 1 by 1 and on the same day as the party, I'd be able to work out which bottle contained poison. |
ZymfSep 19, 2015 4:43 AM
| Empty the wine from all the bottles since it only says he needs the bottles? |
| I've been here way too long... |
Zymf said: But if the servants start drinking of the 999 safe bottles to test if it's poisoned, then there will not be 999 full bottles for the party? Disregarding this fact I'd do the following: Day 1: Split the 1000 bottles in 10 groups of 100 and have the servants take a sip from every single bottle in each group. Day 2: Split each group in half and make 10 new groups and have the servants take a sip from every single bottle in the new groups. Day 3: Split the groups in half again and make 10 new groups so that only 25 of the bottles from Day 1 remains (you get the idea) and have the servants take a sip from every single bottle in the new groups. Day 4-6: Keep splitting the groups in half, forming new unique groups. Day 7: Split the groups in half one last time and have the servants take a sip from every single bottle in the new groups. Since there initially was 100 bottles in each group, there will only be 100*0.5^7 ≈ 1 bottle from from Day 1 remaining in each group. Now I'd wait 2 weeks till my servants would begin dying 1 by 1 and on the same day as the party, I'd be able to work out which bottle contained poison. Does all the servants taste the group? In the second step you split it into half, are you disregarding 500 bottles ? I think the way you think is correct, can you explain your solution properly? TheConquerer said: Lol NoEmpty the wine from all the bottles since it only says he needs the bottles? |
| No, each servant only drink from 100 bottles each day. Also, when you split the groups in half and make new groups, you have to split them "evenly". To make it more simple, lets say there are 10 different colors and 100 bottles of each color. Day 1, you will have each servant choose a color and sip from every bottle of that color. When you split the groups, there have to be half as many red, half as many green and so on. The rest will be passed on to the next servant in the line. When the first servant die, you'll know what color the poisonous drink has and you have effectively limited the number of dangerous bottles to 100. However, because the poison takes 2 weeks to take effect, you have to split all 1000 bottles anew on Day 2 I can't really explain my solution in a simpler way xD |
| The bottle with a broken seal is the poisoned one. Or do you really plan to open one thousand wine bottles and expect the wine to stay good for a party that will happen in four weeks? |
 |
lupadim said: The bottle with a broken seal is the poisoned one. Or do you really plan to open one thousand wine bottles and expect the wine to stay good for a party that will happen in four weeks? Ah...the main focus of the puzzle is not about the container. It's about how you identify the poisonous container with a strategy involving 10 people. |
| @Zymf the answer is similar so I guess it's fine. Answer: |
| I'm the desire of all men, rich and poor. I've caused countless deaths, and no doubt will cause many more. I'm the one thing man can't live without, yet the one thing they all doubt. What am I? |
|
| @El-psy_congroo: My solution was similar in some ways but there was some key differences. Your solution would only take 2 weeks and mine would take 3 weeks. Also, I'm not sure if my solution is actually valid because of the fact that you can't divide odd numbers with 2... @Astro: So deep :o! |
Astros said: I'm the desire of all men, rich and poor. I've caused countless deaths, and no doubt will cause many more. I'm the one thing man can't live without, yet the one thing they all doubt. What am I? A woman? :p |
grave_robber said: No.A woman? :p |
|
Astros said: money?I'm the desire of all men, rich and poor. I've caused countless deaths, and no doubt will cause many more. I'm the one thing man can't live without, yet the one thing they all doubt. What am I? |
 Where there is no imagination there is no horror. || Arthur Conan Doyle || Happy Halloween! |
Astros said: I'm the desire of all men, rich and poor. I've caused countless deaths, and no doubt will cause many more. I'm the one thing man can't live without, yet the one thing they all doubt. What am I? True Love? Cheesy reply |
| I've been here way too long... |
Suzune-chan said: No.money? TheConquerer said: No. Like SwissTrue Love? Cheesy reply |
|
| Hmm heres my second shot Freedom? Thats all from me :P |
| I've been here way too long... |
TheConquerer said: Ding Ding. Winner winner chicken dinner. I tried making it tricky in using the archaic definition of doubt in the last sentence. Either it was that or the ambiguity that made it difficult.Hmm heres my second shot Freedom? Thats all from me :P |
|
| Woooooo Yeah the doubt definitely threw me off since it sounds strange to say people doubt freedom. Anyways I'll post a simple one and go to bed. "Poor Edmund Dantes has been captured by evil forces and thrown in prison, there he is put in the torture chamber and faces the evil torturer, Maldovak. Being a man who enjoys teasing his victims Maldovak walks up to Edmund and bellows! " Edmund! I will let you tell me any statememt, if it is a true one I will burn you till your skin peels and if it false I will drown you till you die! What will you choose?" Edmund choose his words very carefully and Maldovak was forced to let him free being the simple brute he was." What did Edmund say? |
| I've been here way too long... |
TheConquerer said: You're a liar.Woooooo Yeah the doubt definitely threw me off since it sounds strange to say people doubt freedom. Anyways I'll post a simple one and go to bed. "Poor Edmund Dantes has been captured by evil forces and thrown in prison, there he is put in the torture chamber and faces the evil torturer, Maldovak. Being a man who enjoys teasing his victims Maldovak walks up to Edmund and bellows! " Edmund! I will let you tell me any statememt, if it is a true one I will burn you till your skin peels and if it false I will drown you till you die! What will you choose?" Edmund choose his words very carefully and Maldovak was forced to let him free being the simple brute he was." What did Edmund say? |
|
| I'll drown |
You will be what you will to be. |
| Hm, there is an easy answer to this one, but I just can't figure it out |
Where there is no imagination there is no horror. || Arthur Conan Doyle || Happy Halloween! |
Switch-kun said: I'll drown Correct though its less elegant than I would've wished... |
| I've been here way too long... |
| :P Okay, so here's another two level riddle (if you solved one, then solve the next, more difficult one) - You have 10 bags full of coins, in each bag are 1,000 coins. But one bag is full of forgeries, and you can't remember which one. But you do know that a genuine coin weighs 1 gram, but forgeries weigh 1.1 grams. To hide the fact that you can't remember which bag contains forgeries, you plan to go just once to the central weighing machine to get one accurate weight. How can you identify the bag with the forgeries with just one weighing? 2nd part - What if you didn't know how many bags contain forgeries? |
You will be what you will to be. |
| You just weigh: 1 coin from the 1st bag 10 coins from the 2nd bag 25 coins from the 3rd bag 50 coins from the 4th 75 coins from the 5th 100 coins from the 6th bag 250 coins from the 7th bag 500 coins from the 8th bag 750 coins from the 9th bag 1000 coins from the 10th bag If it weighs 2861 it's the 10th bag If it weighs 2836 it's the 9th bag If it weighs 2811 it's the 8th bag ... and so on Second part Instead of just random number of coins from each bag, I think you'll have to make sure that you take at least twice as many coins for each new bag. For example you can take: - 1 coin from the 1st bag - (1*2) = 2 coins from the 2nd bag - (2*2) = 4 coins from the 3rd bag - (4*2) = 8 coins from the 4th bag ... and so on If both bag 1, 2 and 3 contains forgeries, you'll be able to work it out because (1+2+4)*0.1 doesn't exceed 8*0.1 |
| Correct |
You will be what you will to be. |
Zymf said: Also about the last part :o? Draw a line that passes through each box edge only once. You can start and end anywhere you want.  I assume that the line should come out of box in this question. If it's the case it's not possible. Reason: If it's a _._._ |_|_|_| |_|_|_| The line can come out. But in the diagram the two lines are merged, which makes it impossible. Need two more edges to make it possible. I'm not sure about my reasoning. |
El-Psy_Congroo said: The line he is drawing is just an example. The actual puzzle itself looks like this:I assume that the line should come out of box in this question.  You can start inside one of the boxes or outside, it's your choice. As long as it's 1 continious line, everything goes. You are right that it is impossible.. but your reasoning isn't quite what I'm looking for. |
| The question confuses me a bit, are we passing a line through 1 edge of each box maximum? Or passes through all edges but only once? |
 |
| Poke a hole in the paper and draw on the other side? I'm too lazy to take a picture and show how but it should work. |
| I've been here way too long... |
| No, I told you it was impossible ^^ Every time you enter a box you must also exit a box. There are only 2 exceptions to this rule and that is when you begin and end your line. There are 3 boxes with an un-even number of edges and therefore it is theoretically impossible. Your turn to post a riddle Conquerer :D |
| Well yeah but thats why we poke a hole, its like a wormhole :D Anyway heres my riddle "A conquerer is asked to provide a good riddle but can't think of any, what does he do?" Tell me when you find the answer |
| I've been here way too long... |
| I didnt actually Google any of my riddles, I just remember them from an old book I had. Speaking of which I remembered another riddle "Sir Lancelot is on his way to to Saint Ives where he met a man with seven wives, Each wife had seven sacks, Each sack had seven cats, Each cat had seven kits: Kits, cats, sacks, and wives, How many were there going to Saint Ives?" |
| I've been here way too long... |
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