THIS GAME IS CALLED BRAINies (You have to use your brain to answer correctly and it involves math and physics =D) You must have/open an account at the bank to participate in this GAME Game Mechanics 1. I will give set of problems for you to solve 2. the first one to answer correctly will receive 10 CMCC COINS in his account. 3. the 2nd to answer correctly will receive 5 CMCC COINS 4. the rest that have answered the problem correctly will receive 1 CMCC COINS *Coins will be directly added to your account* Here's the 1st problem: Calculate the distance traveled by a train with the ave. speed of 120km/hr in 24hrs. express it in meter/second (speed) the distance can be in KM or M.. Good Luck!!! *chuckles* |
DropOutSep 11, 2010 6:33 AM
| Distance = 2880 km 33.3 meter/second I dont know its correct XD ~Correct~ +10 CMCC Coins |
DropOutSep 11, 2010 6:36 AM
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Problem #2 Find the Circumference of a table with radius of a 5m. multiply the answer by the value of pi 10x. what will be the answer? ^_^ |
| 314? Incorrect : Please read the question again ^_^ |
DropOutSep 12, 2010 1:10 AM
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| Let me try this. :D pi = 3.143 radius, r = 5 meter diameter, d = 2*r = 2*5 = 10 meter circumference = pi*d = 3.143*10 = 31.43 answer by multiply 10 times pi = 31.43*(3.143*10) = 987.8449 Answer = 987.8449 meter I wish this is true answer. Haha... :P ~Correct~ +10 CMCC Coins |
DropOutSep 12, 2010 1:28 AM
 MAL: Massive Card Collections || *NEW! Request Pokémon Custom Collections Card! Others: MV subbed || Blogger || Audio Projects || Don't open this! |
Problem #3 Projectile Motion =D A man throw a rock from a cliff 30m high, the velocity of the rock is 30m/s. Find the Distance of the rock from the base of the cliff after it landed on the ground. ^_^ +15 CMCC coins to the first one to answer |
| Incorrect |
DropOutSep 12, 2010 11:07 PM
| MAL: Massive Card Collections || *NEW! Request Pokémon Custom Collections Card! Others: MV subbed || Blogger || Audio Projects || Don't open this! |
| I have more problem understanding the probelm than solving it Time to touch the ground: High of the Cliff=(Fall Time)²*Gravitation/2 30=10*t²/2 t=sqrt(6)=2,44 Distance= (Fall Time)*velocity=2,44*30=73,2 meters Incorrect --- pretty pretty close though.. Hint: t=2.47s. =D |
DropOutSep 12, 2010 11:08 PM
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| Time to touch the ground: High of the Cliff=(Fall Time)²*Gravitation/2 30=9,8*t²/2 t=sqrt(6,122)=2,47 Distance= (Fall Time)*velocity=2,47*30=74,1 meters In the Tests my teacher said to always use 10 instead of 9,8 because it's easier to count so i kind got used to it... ~Correct~ +15 CMCC Coins Well we use 9.8 for accuracy XD |
DropOutSep 13, 2010 2:28 AM
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Problem #3 (Simple) Speed A car is traveling at 100km/hr for 4hrs and 120km/hr for 5hrs. Q: What is the average Speed of the car? |
~Correct~ +10 CMCC coins |
DropOutSep 13, 2010 5:15 AM
| ~Correct~ +5 CMCC coins |
DropOutSep 13, 2010 7:07 PM
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| Incorrect |
DropOutSep 13, 2010 7:08 PM
| MAL: Massive Card Collections || *NEW! Request Pokémon Custom Collections Card! Others: MV subbed || Blogger || Audio Projects || Don't open this! |
Problem #4 Acceleration A train travels at 10m/s for 5hrs and 20m/s for 6hrs. Q: What is the (Average) Acceleration of the train (from 10m/s to 20m/s) express your answer in m/s^2? (sorry if it's confusing @_@) |
| V=Vo+at V=20m/s---Final V Vo=10m/s---- First V t=5h=5*3600s ---- It takes 5 hours to change to 20m/s. 20=10+a*5*3600 20-10=a*5*3600 10=a*5*3600 a=1/1800 m/s² ~Correct~ +10 CMCC Coins The answer in decimal is 5.5.....X10-4 XD |
DropOutSep 14, 2010 3:09 AM
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Problem #5 Acceleration A train travels 70mi/min for 50mi and another 50mi for 45mins. Q: What is the Final Velocity or Vf? |
| Incorrect |
DropOutSep 15, 2010 2:06 AM
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| Incorrect |
DropOutSep 15, 2010 2:07 AM
Incorrect |
DropOutSep 15, 2010 2:10 AM
 |
Regarding the problem above the acceleration should be negative cause the train moves slower than 70mi/min.. and sorry of the problem is confusing I made it in a whim.. (I'm confused myself) but the answer should be (I think XD) a= -1.82mi/min, Vf=17.14mi/min Okay let's move on.. all the people who tried to answer it receives +5 CMCC Coins and +8 CMCC Coins to EminentFaith for providing his/her computation XD Problem #6 A Motorcycle travels 50km/hrs,he pull the breaks and it took him 45sec. to stop. Q: The Distance it took to make the motorcycle stop. (Sorry for my bad english @__@(I know it's a pain)) |
| V=50km/h=13,89m/s Vf=Vo+at a=(Vf-Vo)/t= -13,89/45 m/s² S=Vo*t + at²/2 S=13,89*45 + (-13,89/45)*45*45/2 S=625,05 - 13,89*45/2=312,525m Incorrect --- It's just simple speed just use S=D/T.. +3 CMCC Coins for trying ^_^ |
DropOutSep 15, 2010 11:02 PM
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| ~Correct~ +10 CMCC Coins |
DropOutSep 16, 2010 2:40 AM
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| ~Correct~ +5 CMCC Coins |
DropOutSep 16, 2010 3:44 AM
Problem #7 A race car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Q: Determine the acceleration of the car and the distance traveled. |
| Acceleration Correct +5 CMCC Coins Distance Incorrect |
DropOutSep 16, 2010 11:18 PM
| V=46.1 Vo=18.5 t=2.47s Velocity Variation=V-Vo=46.1 - 18.5=27.6m/s a=Velocity Variatio/t=27.6/2.47=11.17 meters per square second S=Vo*t+a*t*t/2 S=18.5*2.47+11.17*2.47*2.47/2 S=45,695+34,07=79.76meters ~Correct~ +10 CMCC Coins |
DropOutSep 16, 2010 11:19 PM
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Problem #8 Upton Chuck is riding the Giant Drop at Great America. If Upton free falls for 2.6 seconds. Q: What will be his final velocity and how far will he fall? |
| Vf is Correct +5 CMCC Coins you forgot to answer the distance ^_^ |
DropOutSep 17, 2010 3:58 AM
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| Sorry,did not know that u were also asking the distance. S=So + Vo*t + g*t*t/2 S=0 + 0*2.6 + 9.8*2.6*2.6/2 = 33.124m ~CORRECT~ +5 CMCC Coins |
DropOutSep 18, 2010 3:10 AM
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Problem #9 An airplane accelerates down a runway at 3.20 m/s2 for 32.8 s until is finally lifts off the ground. Q: The distance traveled before takeoff. |
| t=32.8 a=3.2 Vo=0 So=0 S=So+Vo*t+a*t*t/2 S=0+0*32.8+3.2*32.8*32.8/2=1721,344m ~Correct~ +10 CMCC Coins your the only person playing this game XD |
DropOutSep 19, 2010 2:19 AM
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Problem #10 A car starts from rest and accelerates uniformly over a time of 5.21 seconds for a distance of 110 m. Q:Determine the acceleration of the car. |
| ~Correct~ +10 CMCC Coins Finally someone new XD |
DropOutSep 19, 2010 3:42 AM
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| S=a*t*t/2 S=110 t=5.21 110=a*5.21*5.21/2 110=13,57205*a a=8,1m/s² This was the better game to make coins!!!Now i will have to share? *child mode on* I came to this topic first!!!! ~Correct~ +5 CMCC Coins guess you have to share it XD |
DropOutSep 19, 2010 10:53 PM
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| After some calculations, I got exactly same answer with what cadu_ got here. So I will go on with answer = 8,1m/s². I hope both of us correct. :D ~Correct~ +5 CMCC Coins It seems only 3-4 people are playing this game XD |
DropOutSep 19, 2010 10:54 PM
| MAL: Massive Card Collections || *NEW! Request Pokémon Custom Collections Card! Others: MV subbed || Blogger || Audio Projects || Don't open this! |
Problem #11 A plane has a takeoff speed of 88.3 m/s and requires 1365 m to reach that speed. Q: Determine the acceleration of the plane and the time required to reach this speed. |
~Correct~ +10 CMCC Coins I'm looking at the solutions ^_^ |
DropOutSep 20, 2010 4:38 AM
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| a = acceleration d = distance Vo = initial velocity V = final velocity t = time Torricelli Equation: V²=Vo²+2*a*d 88.3*88.3=0² +2*a*1365 a=2,856m/s² Normal Velocity Equation: V=Vo+at 88.3=0+2.856*t t=30,92s Damn,he's right XD I think that's it for me.It looks like that DropOut has a diferrent fuse from me and just log in when I'm sleeping(most of the time as least).So it will be dificult to be the first solving the problems. ~Correct~ +5 CMCC Coins You missed it by minutes ^_^ |
DropOutSep 20, 2010 4:40 AM
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Problem #12 Rocket-powered sleds are used to test the human response to acceleration. If a rocket-powered sled is accelerated to a speed of 444 m/s in 1.8 seconds. Q: What is the acceleration and what is the distance that the sled travels? |
| ~Correct~ +5 CMCC Coins for acceleration.. what about distance? ~_^ |
DropOutSep 20, 2010 8:22 PM
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| Acceleration Correct +5 CMCC Coins Distance INCORRECT |
DropOutSep 21, 2010 5:29 AM
| a=246.67m/s2 S=a*t*t/2 S=246.67*1.8*1.8/2=399.6m ~Correct~ + 5 CMCC Coins for Distance |
DropOutSep 21, 2010 11:01 PM
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Problem #13 An engineer is designing the runway for an airport. Of the planes that will use the airport, the lowest acceleration rate is likely to be 3 m/s2. The takeoff speed for this plane will be 65 m/s. Q: Assuming this minimum acceleration, what is the minimum allowed length for the runway? (Distance) |
| ~Correct~ as usual +10 CMCC Coins ^_^ |
DropOutSep 22, 2010 4:52 AM
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| ~Correct~ +5 CMCC Coins |
DropOutSep 22, 2010 7:59 PM
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Problem #14 A kangaroo is capable of jumping to a height of 2.62 m. Q: Determine the takeoff speed of the kangaroo. ( Vi ) |
| ~Correct~ +10 CMCC Coins congratulations to your roommate XD |
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| Final Velocity=V=0 Inicial Velocity=Vo=? aceleration=-9.8(It is the oposite of the Velocity) distance=S=2.62 Toriceli: V²=Vo²+2*a*S -Vo²=2*(-9.8)*2.62 Vo²=2*9.8*2.62 Vo²=51,352 Vo=7.166m/s ~Correct~ +5 CMCC Coins |
DropOutSep 25, 2010 5:24 AM
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| im not sure but i will try ^^ ~Correct~ +5 CMCC Coins |
DropOutSep 25, 2010 5:24 AM
| Signature removed. Please follow the signature rules, as defined in the Site & Forum Guidelines. |
Problem #15 If Michael Jordan has a vertical leap of 1.29 m. Q: What is his takeoff speed and his hang time (total time to move upwards to the peak and then return to the ground)? |
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